Integrand size = 8, antiderivative size = 83 \[ \int \cos \left (a+b x^n\right ) \, dx=-\frac {e^{i a} x \left (-i b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},-i b x^n\right )}{2 n}-\frac {e^{-i a} x \left (i b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},i b x^n\right )}{2 n} \]
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Time = 0.03 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3447, 2239} \[ \int \cos \left (a+b x^n\right ) \, dx=-\frac {e^{i a} x \left (-i b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},-i b x^n\right )}{2 n}-\frac {e^{-i a} x \left (i b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},i b x^n\right )}{2 n} \]
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Rule 2239
Rule 3447
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \int e^{-i a-i b x^n} \, dx+\frac {1}{2} \int e^{i a+i b x^n} \, dx \\ & = -\frac {e^{i a} x \left (-i b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},-i b x^n\right )}{2 n}-\frac {e^{-i a} x \left (i b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},i b x^n\right )}{2 n} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 92, normalized size of antiderivative = 1.11 \[ \int \cos \left (a+b x^n\right ) \, dx=-\frac {x \left (b^2 x^{2 n}\right )^{-1/n} \left (\left (-i b x^n\right )^{\frac {1}{n}} \Gamma \left (\frac {1}{n},i b x^n\right ) (\cos (a)-i \sin (a))+\left (i b x^n\right )^{\frac {1}{n}} \Gamma \left (\frac {1}{n},-i b x^n\right ) (\cos (a)+i \sin (a))\right )}{2 n} \]
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Result contains higher order function than in optimal. Order 5 vs. order 4.
Time = 0.52 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.90
method | result | size |
meijerg | \(x {}_{1}^{}{\moversetsp {}{\mundersetsp {}{F_{2}^{}}}}\left (\frac {1}{2 n};\frac {1}{2},1+\frac {1}{2 n};-\frac {x^{2 n} b^{2}}{4}\right ) \cos \left (a \right )-\frac {b \,x^{1+n} {}_{1}^{}{\moversetsp {}{\mundersetsp {}{F_{2}^{}}}}\left (\frac {1}{2}+\frac {1}{2 n};\frac {3}{2},\frac {3}{2}+\frac {1}{2 n};-\frac {x^{2 n} b^{2}}{4}\right ) \sin \left (a \right )}{1+n}\) | \(75\) |
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\[ \int \cos \left (a+b x^n\right ) \, dx=\int { \cos \left (b x^{n} + a\right ) \,d x } \]
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\[ \int \cos \left (a+b x^n\right ) \, dx=\int \cos {\left (a + b x^{n} \right )}\, dx \]
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\[ \int \cos \left (a+b x^n\right ) \, dx=\int { \cos \left (b x^{n} + a\right ) \,d x } \]
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\[ \int \cos \left (a+b x^n\right ) \, dx=\int { \cos \left (b x^{n} + a\right ) \,d x } \]
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Timed out. \[ \int \cos \left (a+b x^n\right ) \, dx=\int \cos \left (a+b\,x^n\right ) \,d x \]
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